When N2+ is form N2 bond-order ......... and when O2+ is formed from O2 bond-order:
Correct answer: D. Decrease increase
- A. Increases increases
- B. Decreases decreases
- C. Increases decreases
- D. Decrease increase
Explanation
Molecular orbital configuration of N2 is 1s2 2s2 2p3 Molecular orbital configuration of O2 is 1s2 2s2 2p4. When n2+ is formed from n2 electron is removed from sigma- bonding and hence boiling point decreases while o2+ is formed from o2, electron is removed from pie bonding and boiling point increases.
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Chemical bonding explains molecular shape through VSEPR theory and distinguishes sigma bonds from pi bonds. Questions involve hybridization, bond angles, dipole moment and bond energy, including how electron-pair repulsion determines geometry and how bond polarity differs from the overall polarity of a molecule.
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