When ethanoic acid reacts with methylamine, an amide is formed. What is the structure of the amide formed?
Correct answer: D. D
- A. A
- B. B
- C. C
- D. D
Explanation
When ethanoic acid reacts with methylamine, it undergoes a condensation reaction to form an amide. The reaction can be represented as:CH3COOH + CH3NH2 → CH3CONHCH3 + H2OThe product formed is methyl ethanamide, which has the structure CH3-CO-NH-CH3. It is also commonly known as N-methyl acetamide. In the amide, the carbonyl group (C=O) of ethanoic acid reacts with the nitrogen atom of the methylamine, and a peptide bond is formed between them. Amides are important functional groups in biochemistry and are present in many biomolecules such as proteins and nucleic acids.
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About Alkyl Halides
Alkyl halides are named and related to their carbon-halogen structure, polarity and reactivity. The key reactions are nucleophilic substitution by SN1 and SN2 mechanisms and elimination by E1 and E2 mechanisms, including how substrate structure, nucleophile, base, solvent and temperature influence substitution versus elimination.
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