When a particle executes simple harmonic motion, the quantity 4π²f² is equal to:
Correct answer: B. g/l
- A. gl
- B. g/l
- C. l/g
- D. √g/l
Explanation
For a simple pendulum, the angular frequency squared, which is 4 pi squared f squared, equals g divided by l, since the time period is 2 pi times the square root of l over g. Inverting this gives l over g, the common slip.
This question appeared on the UHS MDCAT 2026 paper, which you can sit online with every answer explained.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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