.When a graph is plotted betweenon x-axis and log k on y-axis a straight lineis obtained with a negative slope which has two end in

Explanation

The correct answer for the location of the straight line on the graph between 1/T on the x-axis and log k on the y-axis is:(a) I and II quadrantHere's why the other options are incorrect:(b) II and III quadrant: The slope of the line is negative, meaning as 1/T (inverse of temperature) increases, log k (rate constant) decreases. So, the line can't be in the III quadrant where both x and y values are negative.(c) III and IV quadrant: As explained above, the line can't be in the III quadrant with both x and y negative. In the IV quadrant, both x and y are positive, but with a negative slope, the line cannot reach this quadrant as log k (y-axis) keeps decreasing as 1/T (x-axis) increases.(d) II and IV quadrant: Again, the negative slope and decreasing log k with increasing 1/T rule out the IV quadrant. Therefore, the line can only be in the I and II quadrant where both x and y can be positive or only x is positive (I quadrant) while y (log k) remains negative (II quadrant).