When a force of 4N acts on a mass of 2kg for a time of 2 sec, what is the rate of change of momentum?
Correct answer: B. 4kg ms-2
- A. 2kg ms-2
- B. 4kg ms-2
- C. 8kg ms-2
- D. 16kg ms-2
Explanation
Rate of change of momentum, ∆ P/ ∆ t, is equal to applied force, F. ∆ P/ ∆ t = Fso ∆ P/ ∆ t = F = 4 kg ms-2
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