When a force of 1N displaces its point of application by 1m in the direction of the force, the work done is
Correct answer: A. 1J
- A. 1J
- B. 10J
- C. 0J
- D. 100J
Explanation
The formula for work done (W) is:W=F×d×cosθW = F \times d \times \cos\thetaW=F×d×cosθWhere:W = Work done (in Joules)F = Force (in Newtons)d = Displacement (in meters)θ\thetaθ = Angle between force and displacementGiven:Force = 1NDisplacement = 1mDirection of force = direction of displacement, so θ=0∘\theta = 0^\circθ=0∘ and cos(0) = 1W=1×1×1=1JW = 1 \times 1 \times 1 = 1JW=1×1×1=1J
This question appeared on the UHS MDCAT 2024 paper, which you can sit online with every answer explained.
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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