When 2 - bromopropane is heated with concentrated alcoholic potassium hydroxide, the major product is:
Correct answer: A. Propene
- A. Propene
- B. Propan-1-ol
- C. Propan-2-ol
- D. Potassium Propoxide
Explanation
a) Propene:When 2-bromopropane is heated with concentrated alcoholic potassium hydroxide (KOH), it undergoes an elimination reaction known as dehydrohalogenation. In this reaction, a hydrogen atom and a bromine atom are eliminated from the 2-bromopropane molecule, resulting in the formation of propene (C3H6) as the major product. Propene is an alkene with a double bond between two carbon atoms.
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About Elimination Reactions
Elimination reactions remove a leaving group and a hydrogen atom from adjacent carbon atoms to form an alkene. The topic covers dehydrohalogenation of alkyl halides, E1 and E2 mechanisms, the role of base, solvent and substrate structure, and Zaitsev orientation, which is often contrasted with substitution.
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