When 100 g of calcium carbonate (CaCO₃), molar mass = 100 g/mol) is completely decomposed by heating, how many grams of carbon dioxide are produced?
Correct answer: C. 44 g
- A. 22 g
- B. 28 g
- C. 44 g
- D. 11 g
Explanation
One mole of CaCO₃ (100 g) produces one mole of CO₂ (44 g). Therefore, 100 g CaCO₃ yields 44 g CO₂.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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