What will be the relation for the speed of electron accelerated towards the target in the X-ray tube by applying potential difference 'V', taking the mass of electron 'm' and charge on electron 'e'?
Correct answer: A. v = √(2eV/m)
- A. v = √(2eV/m)
- B. v = √(eV/m)
- C. v = √(2mV/e)
- D. v = √(m/eV)
Explanation
Energy gained by the electron when accelerated through a potential of V volts is E=eV This energy is completely converted to kinetic energy: E= ½ mv2Hence ½ mv2=eV --> v2=2eV/m And hence the velocity of the electron is: √(2Ve/m).
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