What will be the pH of a solution of Mg(OH)2 having 10-³ mol / dm³ concentration?
Correct answer: A. 11
- A. 11
- B. 6
- C. 3
- D. 10
Explanation
In order to calculate this pH, we assume that all of Mg(OH)2 dissociates in solution. As pH + pOH = 14, Calculating pOH first: pOH = -log[OH-] pOH = -log[10-3mol dm-3] pOH = 3 Now, pH + 3 = 14 pH = 14-3 pH = 11
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About Acids, Bases and Salts
Acid and base behaviour is explained through the Bronsted-Lowry transfer of protons and the Lewis donation or acceptance of electron pairs. The topic includes pH, pOH, ionisation and water equilibrium, plus salt formation and hydrolysis, where a salt solution may become acidic, basic or neutral.
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