What will be energy used by the battery if the battery has to drive 6.28 x 10^18 electron with potential difference of 20 V across the terminal?
Correct answer: D. 20 joules
- A. 5 joules
- B. 15 joules
- C. 10 joules
- D. 20 joules
Explanation
To calculate the energy used by the battery, we need to determine the total charge that moves through the battery and apply the formula for electrical work. The total charge (Q) is calculated using the formula Q = ne, where n is the number of electrons (6.28 × 1018) and e is the charge of an electron (1.6 × 10-19 C). Therefore, Q = 6.28 × 1018 × 1.6 × 10-19 C = 1 C.The work done (W), or energy used, by the battery is given by W = Q∆V, where ∆V is the potential difference across the battery terminals (20 V). Thus, W = 1 C × 20 V = 20 J.Therefore, the energy used by the battery is 20 joules. The other options do not correctly apply the relationship between charge, potential difference, and energy to arrive at the correct value.
Last updated
About Current Electricity
Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
Practise Current Electricity
1,052 free Current Electricity MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
0.75 A current flows through an iron wire when a battery of 1.5 volts is connected across its ends. The length of the wire 5.0 m and its cross-sectional area is 2.5 x 10^-7 m2. What is the resistivity of iron?
1.6 mA current is flowing in conducting wire then the number of electrons flowing per second
1 kilo ohm = _ ohm
1 microvolt is
1/Req = 1/Rl + 1/R2 + 1/R3 + ..... +1/Rn is the combination in