What is the value of the current in a wire of 10cm long at the right angle to a uniform magnetic field of 0.5 Weber/m2 when the force acting on the wire is 5N ?
Correct answer: C. 100A
- A. 1A
- B. 10A
- C. 100A
- D. 1000A
Explanation
For a wire perpendicular to the field, F = BIL. Thus I = F/(BL) = 5 N / [(0.5 T)(0.10 m)] = 5 N / 0.05 T m = 100 A, since 1 T m A = 1 N. Students may choose b, 10 A, by using 10 cm as 1 m instead of converting it to 0.10 m.
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About Magnetic Flux Density
Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.
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