What is the value of the current in a wire of 10cm length at the right angle to a uniform magnetic field of 0.5 Weber/m^2, when the force acting on the wire is 5N?

Explanation

Determining Current in a Wire at Right Angle to a Magnetic Field Given Information:- Length of the wire (\( L \)) = 10 cm = 0.1 m- Magnetic field strength (\( B \)) = 0.5 Weber/m²- Force (\( F \)) = 5 NFormula for Magnetic Force on a Wire:The formula \( F = ILB \) describes the magnetic force experienced by a current-carrying wire in a magnetic field, where \( I \) represents the current, \( L \) is the length of the wire, and \( B \) is the magnetic field strength.Explanation of Options:Formula Used:The formula used to find the current (\( I \)) is derived from \( F = ILB \) as follows:\[ I = \frac{F}{LB} \]Correct Calculation:\[ I = \frac{5}{0.1 \times 0.5} = 100 \, \text{A} \]### Explanation of Correct Option (c):The correct value of the current in the wire is calculated using the formula \( I = \frac{F}{LB} \). Substituting the provided values (\( F = 5 \, \text{N} \), \( L = 0.1 \, \text{m} \), \( B = 0.5 \, \text{Weber/m²} \)) gives \( I = \frac{5}{0.1 \times 0.5} = 100 \, \text{A} \). Hence, the correct answer is option (c) 100A, as the calculated current matches this value.