What is the potential difference between two points in an electric field if it takes 600 J of energy to move a charge of 2 C between these two points?
Correct answer: C. 300 J
- A. 1200 J
- B. 800 J
- C. 300 J
- D. 0 J
Explanation
To find the potential difference (V) between two points in an electric field, you can use the formula: v=W/Q Where: V is the potential difference. W is the work done (energy). Q is the charge. In this case: W = 600 J (work done) Q = 2 C (charge) Now, let's calculate the potential difference (V): V=600J/2C V=300J
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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