What is the potential difference between two points in an electric field if it takes 600 J of energy to move a charge of 2 C between these two points?
Correct answer: C. 300 J
- A. 1200 J
- B. 800 J
- C. 300 J
- D. 0 J
Explanation
To find the potential difference (V) between two points in an electric field, you can use the formula: v=W/Q Where: V is the potential difference. W is the work done (energy). Q is the charge. In this case: W = 600 J (work done) Q = 2 C (charge) Now, let's calculate the potential difference (V): V=600J/2C V=300J
Last updated
About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
Practise Electrostatics
831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1/C_eq = 1/C_1 + 1/C_2 + 1/C_3 + ... + 1/C_n
1 N/C equals to:
1 volt x 1 ampere is equal to:
10 V potential difference is applied across the plate of the 1 µF capacitor. What is the energy stored in the capacitor?
12 J work is to be done against an existing electric field to take a charge of 0.01C from A to B. Find the potential difference between B and A: