What is the order of a chemical reaction of the bellow figure, if the rate of formation of 'C', increases by a factor of 2.82 on doubling the concentration of 'A' and increases by a factor of 9 on trebling the concentration of 'B' ?
Correct answer: A. 7/2
- A. 7/2
- B. 7/4
- C. 5/2
- D. 5/4
Explanation
If rate is proportional to A^mB^n, doubling A gives 2^m = 2.82, so m is approximately 1.5; trebling B gives 3^n = 9, so n = 2. The overall order is m+n = 1.5+2 = 7/2.
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