What is the number of moles present in 0.6 grams of silica (SiO₂)? (Atomic mass Si = 28, O = 16):
Correct answer: A. 0.01 mole
- A. 0.01 mole
- B. 0.1 mole
- C. 0.06 mole
- D. 0.6 mole
Explanation
The molar mass of SiO₂ is 28 + (2 × 16) = 60 g/mol. The number of moles is the given mass divided by the molar mass: 0.6 g / 60 g/mol = 0.01 mol.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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