What is the minimum value of x² - 6x + 11 for real x?
Correct answer: B. 2
- A. 1
- B. 2
- C. 3
- D. 4
Explanation
Completing the square gives x² - 6x + 11 = (x - 3)² + 2. The square is at least zero, so the minimum value is 2 when x = 3.
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