What is the mass of Mg3N2 produced if 48 g of Mg metal is reacted with 34 g NH3?3Mg + 2NH3 → Mg3N2 + 3H2
Correct answer: A. 200/3 g
- A. 200/3 g
- B. 24 g
- C. 34 g
- D. 48 g
Explanation
The balanced chemical equation is 3Mg+2NH3→Mg3N2+3H2 48 g of magnesium will react with (48×2×17)/(24×3)=22.67 g of ammonia.However, 34 g of ammonia is present. Thus, magnesium is the limiting reagent.The mass of magnesium nitride formed is 48×1×100/24×3 =200/3 g.
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