What is the energy required to ionize an H-atom from the third excited state, if ground state ionization energy of H-atom is 13.6 eV?
Correct answer: A. 0.85 eV
- A. 0.85 eV
- B. 3.4 eV
- C. 13.6 eV
- D. 12.1 eV
Explanation
Third excited state means fourth energy state so electron have energy:Ionization energy= - En = -Eo/n2= -13.6/16 = - (-0.85 eV) = 0.85eV
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Atoms emit or absorb light at specific wavelengths because electrons occupy quantized energy levels and change levels by absorbing or releasing photons. The topic covers emission and absorption spectra, spectral series, hydrogen’s line spectrum, energy-level transitions, and the relation between wavelength, frequency and photon energy.
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