What is the energy required to ionize an H-atom from the third excited state, if ground state ionization energy of H-atom is 13.6 eV?
Correct answer: A. 0.85 eV
- A. 0.85 eV
- B. 3.4 eV
- C. 13.6 eV
- D. 12.1 eV
Explanation
Third excited state means fourth energy state so electron have energy:Ionization energy= - En = -Eo/n2= -13.6/16 = - (-0.85 eV) = 0.85eV
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