What is the de broglie wavelength of a proton whose linear momentum has a linear magnitude of 3.3 x 10^-23 kg m/s?
Correct answer: C. 0.02nm
- A. 0.0002nm
- B. 0.002nm
- C. 0.02nm
- D. 0.2nm
Explanation
λ = h/p λ = 6.63x10^-34/3.3x10^-23 =2x10^-11 =0.02x10^-9 m =0.02nm
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