Water is flowing through a tube of non-uniform cross- section. Ratio of the radius at entry and exit end of the pipe is 3:2. Then the ratio of velocities at entry and exit of liquid is:
Correct answer: A. 4:9
- A. 4:9
- B. 9:4
- C. 8:27
- D. 1:1
Explanation
v ∝ 1/A and A ∝ r². With r1:r2 = 3:2 ⇒ A1:A2 = 9:4 ⇒ v1:v1 = A2: A1= 4:9.
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