Volume occupied by 4.4g of CO2 at STP is
Correct answer: A. 2.24dm3
- A. 2.24dm3
- B. 22.4dm3
- C. 112cm3
- D. 1.12 dm3
Explanation
No. Of moles (n) = mass/ M.mass=4.4/44 = 0.1 mole Volume = n x 22.414 dm3 = 0.1 x 22.414=2.24 dm3
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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