Using linear approximation near x = 25, what is the approximate value of sqrt(24.3)?
Correct answer: C. 4.93
- A. 4.83
- B. 4.90
- C. 4.93
- D. 5.07
Explanation
For f(x) = sqrt(x), use f(25) = 5 and f'(25) = 1/10. Thus sqrt(24.3) is approximately 5 + (1/10)(-0.7) = 4.93.
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Differentiation covers gradients, standard derivative rules, the product and quotient rules, the chain rule, stationary points and rates of change. Optimisation uses first and second derivatives to classify maxima and minima, while applications include tangent and normal lines, marginal quantities and related rates.
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