Under identical conditions of temperature, the density of gas A is three times that of gas B, while the molecular mass of gas B is twice that of A. The ratio of pressures of A and B will be:
Correct answer: A. 6
- A. 6
- B. 1/6
- C. 2/3
- D. 3/2
Explanation
This is the following solution:To determine the ratio of the pressures of gases A and B, let's use the ideal gas law equation: PV NRTThis equation can also be expressed as p=nM/VTherefore, the number of moles n can be expressed as n PV/MSubstitute n in the ideal gas equation: P pRT/MNow, let pA and pB represent the densities of gases A and B, respectively, and Ma and Mb their molecular masses. According to the problem:pA = 3pB and Mb + 2MaLet's denote the pressures of gases A and B . Using the derived pressure formula for each gas:for gas A: Pa = pa Rt/MaFor gas B: Pb =pb Rt/MbRatio of gas A/ratio of Gas Bso pA/pB = 6
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About Gases
Gas behaviour is explained through the kinetic molecular theory and the relationships among pressure, volume and temperature. Work includes STP, Boyle's and Charles's laws, absolute zero, the ideal gas equation, and the distinction between ideal and real gases, especially the effects of intermolecular forces and molecular volume.
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