Two wires of copper are of the same length but have different diameters. When they are connected in series across a battery, the heat generated is H1 When connected in parallel across the same battery, the heat generated during the same time is H2 then:
Correct answer: B. Hl < H2
- A. H1=H2
- B. Hl < H2
- C. Hl>H2
- D. None of the above
Explanation
In series resistance, R(series) =R1 †R2 So, H1 =V² /R (series) In parallel 1/R (parallel)=1/R¹ † 1/R²So, H2 =V²/R(parallel)Here, the R series is greater than the R parallel.H2 is greater than H1.
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