Two tuning forks produce 6 beats per second. Which of the following are possible frequencies of these tuning forks:
Correct answer: B. 8 Hz and 14 Hz
- A. 12 Hz and 24 Hz
- B. 8 Hz and 14 Hz
- C. 10 Hz and 20 Hz
- D. 66 Hz and 11 Hz
Explanation
Number of beats n= fb-fa [frequencies of tuning forks] So, fb-fa= 6We have to find the option where the difference of two frequencies is equal to Option A: 12-24= 12 which is not equal to 6Option B: 8-14= 6 which is the right optionOption C: 10-20=10 which is not equal to 6Option D: 66-11=55 which is not equal to 6
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About Superposition and Interference
Superposition states that overlapping waves produce a resultant displacement equal to the algebraic sum of their individual displacements. Interference covers constructive and destructive interference, phase difference, path difference, coherent sources, and conditions for maxima and minima. It differs from diffraction, which involves spreading around openings or obstacles.
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