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Two springs (k1 = 100 N/m, k2= 300 N/m) are connected in parallel, and a 2 kg mass is attached. What is the angular frequency of oscillation?

Correct answer: C. 14.14 rad/s

  • A. 5 rad/s
  • B. 10 rad/s
  • C. 14.14 rad/s
  • D. 20 rad/s

Explanation

The equivalent spring constant for parallel springs is keq = k1 + k2 = 100 +300 = 400 N/m. The angular frequency ω = √keq/m = √400/2 = √200 ≈ 14.14rad/s.

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About Simple Harmonic Motion

Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.

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