Two rocket fuels below are determined by their high performance.N2H4(l) + O2(g) -> N2(g) + 2H2O(l) ΔH= -632 kJH2 (g) + ½ O2(g) -> H2O(l) ΔH = -286 kJIf equal masses of hydrazine and hydrogen are used, which of the following has better performance?
Correct answer: C. Hydrogen gas
- A. Hydrazine
- B. Both have equal enthalpy of formation
- C. Hydrogen gas
- D. Cannot be compared
Explanation
The performance of rocket fuel is measured by its enthalpy of combustion, which is the amount of heat released when one mole of the fuel is completely burned in excess oxygen to form its products at standard conditions. The enthalpy of the formation of hydrazine is -632 kJ/mol, and that of hydrogen gas is -286 kJ/mol. Since equal masses of hydrazine and hydrogen are used, we can compare their performances by calculating the amount of heat released per gram of fuel. >For hydrazine, the amount of heat released per gram of fuel is (-632 kJ/mol) / (32 g/mol) = -19.75 kJ/g. >For hydrogen gas, the amount of heat released per gram of fuel is (-286 kJ/mol) / (2 g/mol) = -143 kJ/g. Therefore, hydrogen gas has better performance as a rocket fuel than hydrazine since it releases more heat per gram of fuel.
This question appeared on the NUMS 2019 (cancelled sitting) paper, which you can sit online with every answer explained.
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About Enthalpy
Enthalpy is the heat content of a system measured at constant pressure, and its change indicates whether a reaction or physical process is endothermic or exothermic. The topic covers state functions, enthalpy diagrams, standard enthalpy of formation, combustion and neutralisation, and the relationship between ΔH and internal energy change.
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