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Two projectiles are fired at different angles with the same magnitude of velocity such that they have the same range. At what angles they might have been projected?

Correct answer: C. 25o and 65o

  • A. 35o and 75o
  • B. 10o and 50o
  • C. 25o and 65o
  • D. None of the above

Explanation

For two projectiles fired at the same speed, complementary angles (those that add up to 90 degrees) will result in the same range. This is due to the symmetry of the sine function in the range equation: R = (v2 * sin(2θ)) / g. Only the angles 25o and 65o are complementary, thus they will have the same range. Options A and B do not sum to 90 degrees, and therefore do not meet the criteria for having the same range. Option D is incorrect because there is a valid answer in option C.

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About Force and Motion

Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.

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