Two monochromatic radiations X and Y are incident normally on a diffraction grating. The second-order intensity maximum for X coincides with the third-order intensity maximum for Y. What is the ratio => wavelength of X/ wavelength of Y
Correct answer: C. 2/3
- A. 1/2
- B. 3/2
- C. 2/3
- D. 2/1
Explanation
Explanation: For a diffraction grating, the condition for intensity maxima is given by dsinθ=mλ, where d is the grating spacing, θ is the angle of diffraction, m is the order of the maximum, and λ is the wavelength.For the given scenario, the second-order intensity maximum for X (=2mX =2) coincides with the third-order intensity maximum for Y (mY =3). Therefore, we can set up the ratio:λY λX =mY mX =32.
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