Two linked genes a and b show 20% recombination. The individuals of a dihybrid cross between ++/ ++ × ab/ab shall show gametes:
Correct answer: C. ++ : 40 : : ab : 40 : : + a : 10 : : + b : 10
- A. ++ : 80 : : ab : 20
- B. ++ : 50 : : ab : 50
- C. ++ : 40 : : ab : 40 : : + a : 10 : : + b : 10
- D. ++ : 30 : : ab : 30 : : + a : 20 : : + b : 20
Explanation
Correct option is C.The combined linkage frequency between the parental combinations ++ and ab is 80%The combined recombination frequency between the recombinant combination +a and +b is 20%The individual frequencies would be half of the combined.So, the correct option is ' ++40 : ab40 : +a10 : +b10'.
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About Inheritance
Mendel's laws explain segregation, independent assortment and the prediction of genetic ratios using alleles, genotypes and phenotypes. The chapter also covers linked genes, recombination and crossing over during meiosis, then applies pedigree reasoning to X-linked recessive traits, which show different inheritance patterns in males and females.
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