Two identical springs (k = 150 N/m) are connected in series. What is the equivalent spring constant?
Correct answer: B. 75 N/m
- A. 50 N/m
- B. 75 N/m
- C. 100 N/m
- D. 150 N/m
Explanation
For springs in series, the equivalent spring constant keq is given by 1/keq = 1/k1 + 1/k2 . Since both springs have the same k, 1/keq = 2/k . Thus, keq =k/2 = 150/2 = 75 N/m.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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