Two identical pendulums (L = 1m, m = 0.2 kg) are coupled by a weak spring (K = 0.1 N/m). Find the frequency of the beat phenomenon:
Correct answer: A. 0.025 Hz
- A. 0.025 Hz
- B. 0.050 Hz
- C. 0.075 Hz
- D. 0.100 Hz
Explanation
Beat frequency fbeat = |f1 - f2|.With f = 1/2π and weak coupling,fbeat ≈ K/4πmfo ≈ 0.025 Hz.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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