Two forces are applied to a 5.0 kg crate; one is 6.0N to the north and the other is 8.0N to the west. The magnitude of the acceleration of the crate is:
Correct answer: C. 2.0m/s2
- A. 0.50m/s2
- B. 2.8m/s2
- C. 2.0m/s2
- D. 10m/s2
Explanation
Explanation is given below.We will use the formula F= ma to find the acceleration a but will have to calculate the resultant force F for it first.Draw a vector diagram of the forces in the direction mentioned and form a complete rectangle (as made in blue lines in the diagram). The red line shows the resultant velocity. Use Pythagoras theorem to find the resulstant force, from the right-angle triangle shown below. F = √(82 + 62) F = √(64 + 36)F= √100 = 10So resultant force is 10NF= maa = F/ma = 10/5a = 2ms-2
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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