Two forces, 5 N and 10 N are acting at 'O' and 'P' respectively on a uniform rod of 100 cm is suspended at the position of center of gravity 50 cm mark as shown in the figure. What is position of P on meter rod?
Correct answer: B. 75 cm
- A. 80 cm
- B. 75 cm
- C. 70 cm
- D. 65 cm
Explanation
For the rod to be balanced, the clockwise moment must be equal to the anticlockwise moment.5×50=10×xx=25cm 50+25=75cm.250/10=xAs it is a numerical, it can have only one possible answer.
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