Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are;

Correct answer: C. 9I and I

  • A. 5I and I
  • B. 5I and 3I
  • C. 9I and I
  • D. 9I and 3I

Explanation

Amplitudes ∝ √I. Max intensity Imax = (√I + √4I)² = (1+2)² I = 9I. Min intensity Imin = (1−2)² I = 1 I. Thus extremes are 9I and I.

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