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Two charges each equal to 2µC are 0.5m apart. If both of them exist inside a vacuum, then the force between them is

Correct answer: B. 0.144N

  • A. 2.44N
  • B. 0.144N
  • C. 1.89N
  • D. 3.144N

Explanation

Let the two charges be Q1 & Q2 and according to coulomb's force, F=kq1q2where, ATQ, F=9N R=d⇒9=KQ1 Q2 /d2 9d2=KQ1 Q2 ⟶(1)Now, in 2nd case when d→3d, force is given by,F1=(3d)2KQ1 Q2 =9d2KQ1 Q2 ⟶(2)Substituting (2) into (1) will result to F1=KQ1 Q2 =1N THUS THIS IS THE CORRECT ANSWER

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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.

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