Two charges are placed at a certain distance. If the magnitude of each charge is doubled, the force will become
Correct answer: C. 4 times of original value
- A. 1/4th of its original value
- B. 1/8th of its original value
- C. 4 times of original value
- D. 8 times of original value
Explanation
Electric force is given by F=Kq1q2/r2. Here q1 and q2 are the magnitudes of the point charges and r is the distance between them. If the magnitude of each charge is doubled it becomes q1'=2 q1 and q2'=2 q2 . The new force F' is F'= Kq1'q2'/r2 = K(2q1)(2q2 )/r2 = 4Kq1q2/r2 = 4F.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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