Two capacitors C1 (6μF) and C2(12μF) are in series across a 180 volts d.c. supply. Calculate the potential difference across each capacitor (C1 and C2).
Correct answer: B. 120 volts ... 60 volts
- A. 98 volts ... 32 volts
- B. 120 volts ... 60 volts
- C. 68 volts ... 96 volts
- D. 30 volts ... 65 volts
- E. 25 volts ... 25 volts
Explanation
Since the voltage is INVERSELY proportional to the capacitance, according to the formula: Q=CV, the voltage division is also in the same way. Since the capacitance ratio is 1:2, the voltage division is 2:1. Hence the correct division of 180V voltage will be 120 V and 60V.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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