Two capacitors C1=3 uF and C2=6 uF are in series across a 90 volts D.C. supply. The total capacitance is given by:
Correct answer: B. 2 uF
- A. 9 uF
- B. 2 uF
- C. 10 uF
- D. 90 uF
- E. 5 uF
Explanation
1/C1 + 1/C2 = 1/C⅓ + ⅙ = 1/C2 + 1 /6 = 1/C3/6 = 1/C½ =1 /CC = 2 uF
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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