Two capacitors C1 (12 F) and C2 (24 F) are connected in series across a 36 V supply. The charge stored on each of them will be:
Correct answer: A. 288 C, 288 C
- A. 288 C, 288 C
- B. 4770 C, 4770 C
- C. 5810 C, 6610 C
- D. 7170 C, 8140 C
Explanation
In series, charge remains same. This cancels option C and D.To calculate Total capacitance:1/C = 1/12 + 1/24 C=8FC=Q/V8 x 36= 288COption A is therefore the correct answer.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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