Two capacitors 6μf and 12μf are in series connected across a 200 volts D.C. supply, Calculate the charges on each capacitor, respectively.
Correct answer: A. 8 x 10^-4 C, 8 x 10^-4 C
- A. 8 x 10^-4 C, 8 x 10^-4 C
- B. 8μC, 8μC
- C. 8 x 10^4C, 16 x 10^4C
- D. 800C, 800C
Explanation
As C1= 6µF C2 = 12µF V = 200V Ceq = 6(12)/18 = 4µF Q = CV = 4 ×10^-6 × 200 = 8 × 10^-4C In series, charge remains same, so same charge will flow through both capacitors. Hence, option A is correct.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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