Two bodies 'x' and 'Y' are attached to the ends of a string which passes over a pulley so that the two bodies hang vertically. If the mass of the body 'x' is 5 kg and that of body 'Y' is 4.8 kg. Find the acceleration?(g = 9.8 m/s^2)
Correct answer: A. 0.2 m/s2
- A. 0.2 m/s2
- B. 1.7 m/s2
- C. 3.7 m/s2
- D. 4.9 m/s2
- E. 9.1 m/s2
Explanation
The acceleration of the system can be found using Newton's second law. The net force on the system is the difference in weight of the two masses: F = (mx - my) * g. Here, mx = 5 kg and my = 4.8 kg, and g = 9.8 m/s2. Therefore, the net force F = (5 - 4.8) * 9.8 = 0.2 * 9.8 = 1.96 N. The total mass of the system is 5 + 4.8 = 9.8 kg. To find acceleration, use the formula a = F / (mx + my), which gives a = 1.96 / 9.8 = 0.2 m/s2. Thus, the correct answer is Option A: 0.2 m/s2. The other options do not correctly account for both masses or the net force in the system.
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