Transfer of heat from cold to hot place in refrigerator mechanism is an example of:
Correct answer: B. Non-Spontaneous reaction
- A. Spontaneous reaction
- B. Non-Spontaneous reaction
- C. First law of thermodynamics
- D. All of the above options are correct
Explanation
In this case:Heat is being transferred from hot surroundings to the cold interior of a refrigerator, which is against the natural direction of heat flow.This process requires work, done by the refrigerator's compressor, which uses electrical energy to move heat from a colder region to a hotter one.According to the Second Law of Thermodynamics, heat cannot flow from cold to hot spontaneously.It can only happen when external energy is supplied - so the process is non-spontaneous.
Last updated
About Thermochemistry and Energetics of Chemical Reactions
Thermochemistry measures energy changes in chemical reactions and distinguishes exothermic from endothermic processes. Work covers systems, surroundings and state functions, internal energy, the first law of thermodynamics, enthalpy and Hess's law, including the sign conventions used when heat enters or leaves a system.
Practise Thermochemistry and Energetics of Chemical Reactions
728 free Thermochemistry and Energetics of Chemical Reactions MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1/2 H2(g) ➞ H(g) ∆H = 218 kJ mol-1.In this reaction, ∆H will be called:
1 Kcal is equal to:
2P(s) 3CI2(g) 2PCI3 ∆H= 151.8 kJ PCl3+ CI2(g) , PCI5(g); ∆H = -32.8 kJFrom the following data, the heat of formation of PCI5 comes out to be :
5 calories are equivalent to _ Joule.
5 mole of an ideal gas expand reversibly from a volume of 8 dm3 to 80 dm3 at a temperature of 27°C. Calculate the change in entropy.