Tobacco contains a poisonous alkaloid called Nicotine. The molecular formula ofnicotine is C10H14N2 (molar mass = 162.23g). The mass percentage of nitrogen innicotine, is?
Correct answer: D. 17.3%
- A. 4.32%
- B. 8.23%
- C. 12.4%
- D. 17.3%
Explanation
The mass percentage of nitrogen in nicotine can be calculated as follows:Calculate the molar mass of nicotine:Molar mass of nicotine=10×12.01+14×1.01+2×14.01=162.23 g/molCalculate the mass of nitrogen in one mole of nicotine:Mass of nitrogen=2×14.01=28.02 g/molCalculate the mass percentage of nitrogen in nicotine:Mass percentage of nitrogen = Mass of nitrogen Molar mass of nicotine ×100% = 28.02162.23 ×100% ≈ 17.3% Therefore, the answer to your question is d. 17.3%.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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