To get a peak load voltage of 40 volts out of a bridge rectifier, what should be the approximate r.m.s value of the secondary voltage?
Correct answer: C. 28.3V
- A. 0V
- B. 14.4V
- C. 28.3V
- D. 56.6V
Explanation
Vm = 40V Vrms = (Vm /√2) = (40 / √2) = 28.28V ∴ To get Vm of 40V at the output, Vrms of secondary voltage has to be 28.28V
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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