To design a resonant circuit of frequency 100 kHz with an inductor of inductance 5 mH, we need a capacitor of capacitance
Correct answer: D. 507 pF
- A. 5.07 pF
- B. 50 pF
- C. 0.507 pF
- D. 507 pF
Explanation
The resonant frequency is f = 1 / (2π√LC). Rearranging to solve for capacitance gives C = 1 / (4π²f²L). Plugging in the given values for frequency and inductance correctly calculates the required capacitance to be approximately 507 pF.
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Alternating current varies periodically, so phase relationships become essential when current passes through a resistor, capacitor or inductor. The chapter distinguishes resistance from capacitive and inductive reactance, explains phase lead and lag, and connects changing electric and magnetic fields with the production and properties of electromagnetic waves.
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