Three capacitors of 4μF each are connected in such a way that net capacitance of their combination is 6μF. It is possible if:
Correct answer: C. Two in series and one in parallel
- A. All the three in series
- B. All the three in parallel
- C. Two in series and one in parallel
- D. Two in parallel and one in series
Explanation
If two capacitors are connected in series and the resulting combination is in parallel with the third capacitor,Two capacitors in series: 1/Cseries=1/C1 +1/C2 =1/4μF+1/4μF =1/2μF Cseries=2μFThe resulting combination in series with the third capacitor: Ctotal =Cseries+C3 =2μF +4μF =6μF So, the total capacitance is 6μF. Therefore, it is possible if two capacitors are connected in series and the resulting combination is in parallel with the third capacitor.
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About Capacitors
Capacitors store electric charge and energy in an electric field between conductors. Work includes capacitance, the relation Q = CV, dielectric materials, charging and discharging, energy formulas, and combinations of capacitors in series and parallel. Electric potential difference is needed to understand why charge and stored energy change.
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