Three blocks of masses m1, m2, and m3 are connected by massless strings as shown in the figure on a frictionless table. If m1= 10 kg, m2= 6 kg, and m3= 4 kg, the total force acting on the system is 40N, then the tension T2 will be:
Correct answer: C. 32 N
- A. 10 N
- B. 20 N
- C. 32 N
- D. 40 N
Explanation
This is the following solution: The total mass of the system = 20kg The total mass of the system =20kgA ∴ A = F/m = 40N/20kg = 2 m/s2 Because string t2 pulls 1 and 2 blocks, therefore; t2 = (m1 +m2)a= (10+6)×2= 32N.
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