This gas cannot be liquefied by Linde's method
Correct answer: D. Helium
- A. Methane
- B. Carbon dioxide
- C. Hydrogen
- D. Helium
Explanation
Helium is non-polar, so it is not easy to operate attractive forces. So they can't be liquified by Linda's method.
Last updated
About Real and Ideal Gases
An ideal gas is modelled as particles with negligible volume and no intermolecular attraction, obeying Boyle's, Charles's and Avogadro's laws through PV = nRT. Real gases deviate from this behaviour, especially at high pressure and low temperature, because particle volume and attractive forces matter; the van der Waals equation explains these corrections.
Practise Gases
443 free Gases MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
A gas can be liquefied only if it is cooled below its
"a" is called co-efficient of attraction in Van der Waal's equation for real gases the unit of "a" is:
A real gas obeying Van der Waals equation will resemble an ideal gas if both a & b are?
A real gas obeying vander waals equation will resemble the ideal gas if_______________________?
A single chlorine free radical can destroy how many ozone molecules ?